Question: User: y= 6x−20 y, equals, minus, 4, x y= −4x
1. **State the problem:**
We are given two expressions for $y$:
$$y = 6x - 20$$
and
$$y = -4x$$
We want to find the value of $x$ where these two expressions are equal.
2. **Set the equations equal to each other:**
$$6x - 20 = -4x$$
3. **Solve for $x$:**
Add $4x$ to both sides:
$$6x + 4x - 20 = -4x + 4x$$
$$10x - 20 = 0$$
4. **Isolate $x$:**
Add $20$ to both sides:
$$10x - 20 + 20 = 0 + 20$$
$$10x = 20$$
5. **Divide both sides by 10:**
$$\frac{\cancel{10}x}{\cancel{10}} = \frac{20}{10}$$
$$x = 2$$
6. **Find $y$ by substituting $x=2$ into one of the original equations:**
Using $$y = -4x$$:
$$y = -4(2) = -8$$
**Final answer:**
$$x = 2, \quad y = -8$$