Subjects algebra

Solve Linear Equation 30Bcd4

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Question: d) -4(z - 12) = 42
1. **State the problem:** Solve the equation $$-4(z - 12) = 42$$ for the variable $$z$$. 2. **Use the distributive property:** Multiply $$-4$$ by each term inside the parentheses. $$-4(z - 12) = -4 \times z + (-4) \times (-12) = -4z + 48$$ So the equation becomes: $$-4z + 48 = 42$$ 3. **Isolate the variable term:** Subtract $$48$$ from both sides. $$-4z + 48 - 48 = 42 - 48$$ $$-4z = -6$$ 4. **Divide both sides by $$-4$$ to solve for $$z$$:** $$z = \frac{-6}{-4}$$ 5. **Simplify the fraction:** $$z = \frac{\cancel{-6}}{\cancel{-4}} \times \frac{1}{1} = \frac{6}{4}$$ 6. **Reduce the fraction to simplest form:** $$z = \frac{3}{2}$$ **Final answer:** $$z = \frac{3}{2}$$