Solve Linear Equation 571598

1. **State the problem:** Solve the equation $$8 \cdot 13 = -2(3 - 4) + 3y$$ for $$y$$. 2. **Rewrite the equation:** The original equation is $$8 \cdot 13 = -2(3 - 4) + 3y$$. 3. **Calculate the left side:** $$8 \cdot 13 = 104$$, so the equation becomes $$104 = -2(3 - 4) + 3y$$. 4. **Simplify inside the parentheses:** $$3 - 4 = -1$$, so $$104 = -2(-1) + 3y$$. 5. **Multiply:** $$-2 \times -1 = 2$$, so $$104 = 2 + 3y$$. 6. **Isolate the term with $$y$$:** Subtract 2 from both sides: $$104 - 2 = 2 + 3y - 2$$ $$\cancel{104} - 2 = \cancel{2} + 3y$$ $$102 = 3y$$. 7. **Solve for $$y$$:** Divide both sides by 3: $$\frac{102}{3} = \frac{3y}{3}$$ $$34 = y$$. **Final answer:** $$y = 34$$.