Question: User: 5(-8+x)=6x+1/5
1. **State the problem:** Solve the equation $$5(-8+x)=6x+\frac{1}{5}$$ for $$x$$.
2. **Write the equation:** $$5(-8+x)=6x+\frac{1}{5}$$.
3. **Distribute the 5 on the left side:** $$5 \times -8 + 5 \times x = -40 + 5x$$.
4. **Rewrite the equation:** $$-40 + 5x = 6x + \frac{1}{5}$$.
5. **Bring all $$x$$ terms to one side and constants to the other:** Subtract $$5x$$ from both sides:
$$-40 + \cancel{5x} = 6x - \cancel{5x} + \frac{1}{5}$$
which simplifies to
$$-40 = x + \frac{1}{5}$$.
6. **Isolate $$x$$ by subtracting $$\frac{1}{5}$$ from both sides:**
$$-40 - \frac{1}{5} = x + \cancel{\frac{1}{5}} - \cancel{\frac{1}{5}}$$
7. **Calculate the left side:**
Convert $$-40$$ to a fraction with denominator 5: $$-40 = \frac{-200}{5}$$.
So,
$$\frac{-200}{5} - \frac{1}{5} = \frac{-201}{5}$$.
8. **Final solution:**
$$x = \frac{-201}{5}$$.
**Answer:** $$x = \frac{-201}{5}$$ or $$x = -40.2$$.