Question: User: 4(3x-1)=8
1. **State the problem:** Solve the equation $$4(3x-1)=8$$ for $$x$$.
2. **Use the distributive property:** Multiply $$4$$ by each term inside the parentheses:
$$4 \times 3x = 12x$$
$$4 \times (-1) = -4$$
So the equation becomes:
$$12x - 4 = 8$$
3. **Isolate the variable term:** Add $$4$$ to both sides to move the constant term:
$$12x - 4 + 4 = 8 + 4$$
$$12x = 12$$
4. **Solve for $$x$$:** Divide both sides by $$12$$:
$$\frac{\cancel{12}x}{\cancel{12}} = \frac{12}{12}$$
$$x = 1$$
5. **Check the solution:** Substitute $$x=1$$ back into the original equation:
$$4(3(1)-1) = 4(3 - 1) = 4(2) = 8$$
The left side equals the right side, so $$x=1$$ is correct.
**Final answer:** $$x=1$$