Subjects algebra

Solve Linear Equation F855B8

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Question: User: y+1/3=2
1. **State the problem:** Solve the equation $$y + \frac{1}{3} = 2$$ for $$y$$. 2. **Formula and rules:** To isolate $$y$$, subtract $$\frac{1}{3}$$ from both sides of the equation. 3. **Intermediate work:** $$y + \frac{1}{3} = 2$$ Subtract $$\frac{1}{3}$$ from both sides: $$y + \frac{1}{3} - \frac{1}{3} = 2 - \frac{1}{3}$$ Simplify left side: $$y = 2 - \frac{1}{3}$$ Convert $$2$$ to a fraction with denominator $$3$$: $$y = \frac{6}{3} - \frac{1}{3}$$ Subtract fractions: $$y = \frac{6 - 1}{3} = \frac{5}{3}$$ 4. **Final answer:** $$y = \frac{5}{3}$$