Solve System 2Fda3E

1. **State the problem:** Solve the system of linear equations: $$-10y + 9x = -9$$ $$10y + 5x = -5$$ 2. **Add the two equations to eliminate $y$: ** $$(-10y + 9x) + (10y + 5x) = -9 + (-5)$$ This simplifies to: $$9x + 5x = -14$$ $$14x = -14$$ 3. **Solve for $x$: ** $$x = \frac{-14}{14}$$ $$x = -1$$ 4. **Substitute $x = -1$ into the second equation to find $y$: ** $$10y + 5(-1) = -5$$ $$10y - 5 = -5$$ $$10y = 0$$ $$y = 0$$ 5. **Check the solution in the first equation: ** $$-10(0) + 9(-1) = -9$$ $$0 - 9 = -9$$ True. 6. **Final answer:** $$x = -1, y = 0$$ Note: The user provided $x=0.2$ and $y=-0.4$ as the intersection point, but solving the system yields $x=-1$ and $y=0$.