Question: 3. Solve each system of equations.
a. \{ 2x - 4y = 20
x = 4
b. \{ y = 6x + 11
2x - 3y = 7
1. **Problem Statement:** Solve the systems of equations given.
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### a. System:
$$\begin{cases} 2x - 4y = 20 \\ x = 4 \end{cases}$$
2. **Step 1:** Substitute $x = 4$ into the first equation:
$$2(4) - 4y = 20$$
3. **Step 2:** Simplify:
$$8 - 4y = 20$$
4. **Step 3:** Isolate $y$:
$$-4y = 20 - 8$$
$$-4y = 12$$
5. **Step 4:** Divide both sides by $-4$:
$$y = \frac{12}{-4}$$
$$y = -3$$
6. **Answer for (a):**
$$x = 4, \quad y = -3$$
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### b. System:
$$\begin{cases} y = 6x + 11 \\ 2x - 3y = 7 \end{cases}$$
7. **Step 1:** Substitute $y = 6x + 11$ into the second equation:
$$2x - 3(6x + 11) = 7$$
8. **Step 2:** Expand:
$$2x - 18x - 33 = 7$$
9. **Step 3:** Combine like terms:
$$-16x - 33 = 7$$
10. **Step 4:** Isolate $x$:
$$-16x = 7 + 33$$
$$-16x = 40$$
11. **Step 5:** Divide both sides by $-16$:
$$x = \frac{40}{-16}$$
$$x = -\frac{5}{2}$$
12. **Step 6:** Substitute $x = -\frac{5}{2}$ back into $y = 6x + 11$:
$$y = 6\left(-\frac{5}{2}\right) + 11$$
$$y = -15 + 11$$
$$y = -4$$
13. **Answer for (b):**
$$x = -\frac{5}{2}, \quad y = -4$$