Question: Solve for $u$.
$-4 = \frac{8}{9} (u - 3)$
$u = [ ]$
1. **State the problem:** Solve the two-step equation $$-4 = \frac{8}{9} (u - 3)$$ for $u$.
2. **Isolate the term with $u$:** To get rid of the fraction $$\frac{8}{9}$$, multiply both sides of the equation by its reciprocal $$\frac{9}{8}$$.
$$-4 = \frac{8}{9} (u - 3)$$
Multiply both sides by $$\frac{9}{8}$$:
$$\frac{9}{8} \times -4 = \frac{9}{8} \times \frac{8}{9} (u - 3)$$
3. **Simplify both sides:**
$$\frac{9}{8} \times -4 = -\frac{36}{8} = -\frac{9}{2}$$
On the right side, the $$\frac{9}{8}$$ and $$\frac{8}{9}$$ cancel out:
$$\frac{9}{8} \times \frac{8}{9} = \cancel{\frac{9}{8}} \times \cancel{\frac{8}{9}} = 1$$
So the equation becomes:
$$-\frac{9}{2} = u - 3$$
4. **Solve for $u$:** Add 3 to both sides to isolate $u$:
$$-\frac{9}{2} + 3 = u - 3 + 3$$
$$-\frac{9}{2} + 3 = u$$
5. **Simplify the left side:** Convert 3 to a fraction with denominator 2:
$$3 = \frac{6}{2}$$
So:
$$-\frac{9}{2} + \frac{6}{2} = -\frac{3}{2}$$
6. **Final answer:**
$$u = -\frac{3}{2}$$