Subjects algebra

Solve X Squared 53D49A

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Question: x² = 25 x² = −25 x² + 5 = 0 x² − 5 = 0 x² = −20 x² = 20 x − 5 = 0 x + 5 = 0
1. We are given a list of equations involving $x$ and need to solve the first one: $$x^2 = 25$$ 2. The formula to solve equations of the form $$x^2 = a$$ is $$x = \pm \sqrt{a}$$, where $a$ is a real number. 3. Applying this formula to $$x^2 = 25$$: $$x = \pm \sqrt{25}$$ 4. Since $$\sqrt{25} = 5$$, the solutions are: $$x = \pm 5$$ 5. This means: - $$x = 5$$ - $$x = -5$$ 6. These are the two real solutions to the equation $$x^2 = 25$$. Final answer: $$x = 5 \text{ or } x = -5$$