Question: Between which two integers does the square root of 130 lie?
1. **State the problem:** We need to find two consecutive integers between which the value of $\sqrt{130}$ lies.
2. **Recall the concept:** The square root of a number $n$ is a value $x$ such that $x^2 = n$.
3. **Find perfect squares near 130:**
- $11^2 = 121$
- $12^2 = 144$
4. Since $121 < 130 < 144$, it follows that:
$$11^2 < 130 < 12^2$$
5. Taking square roots on all parts (noting square root is increasing for positive numbers):
$$11 < \sqrt{130} < 12$$
6. **Conclusion:** The square root of 130 lies between the integers 11 and 12.