Subjects algebra

Sqrt Function Values 44B1Bc

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Question: Find the indicated values for the function $f(x) = \sqrt{5x - 25}$. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. $f(9) = 4.47$ (Round to the nearest hundredth as needed.) B. The function value is not a real number. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. $f(5) = 0$ (Round to the nearest hundredth as needed.) B. The function value is not a real number. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. $f(2) =$ (Round to the nearest hundredth as needed.) B. The function value is not a real number. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. $f(-2) =$ (Round to the nearest hundredth as needed.) B. The function value is not a real number.
1. **State the problem:** We need to find the values of the function $f(x) = \sqrt{5x - 25}$ at $x=9$, $x=5$, $x=2$, and $x=-2$. 2. **Recall the domain rule for square root functions:** The expression inside the square root must be greater than or equal to zero for the function to have real values. That is, $$5x - 25 \geq 0$$ 3. **Solve the domain inequality:** $$5x - 25 \geq 0$$ $$5x \geq 25$$ $$x \geq 5$$ So, the function is defined for $x \geq 5$. 4. **Evaluate $f(9)$:** $$f(9) = \sqrt{5(9) - 25} = \sqrt{45 - 25} = \sqrt{20}$$ Simplify and round: $$\sqrt{20} = \sqrt{4 \times 5} = 2\sqrt{5} \approx 4.4721 \approx 4.47$$ 5. **Evaluate $f(5)$:** $$f(5) = \sqrt{5(5) - 25} = \sqrt{25 - 25} = \sqrt{0} = 0$$ 6. **Evaluate $f(2)$:** Check domain first: $2 < 5$, so inside the root is negative. $$5(2) - 25 = 10 - 25 = -15 < 0$$ Therefore, $f(2)$ is not a real number. 7. **Evaluate $f(-2)$:** Check domain first: $-2 < 5$, so inside the root is negative. $$5(-2) - 25 = -10 - 25 = -35 < 0$$ Therefore, $f(-2)$ is not a real number. **Final answers:** - $f(9) \approx 4.47$ - $f(5) = 0$ - $f(2)$ is not a real number - $f(-2)$ is not a real number