Question: Work out $\sqrt{38} \times \sqrt{38}$
Give your answer in its simplest form.
1. **State the problem:** We need to calculate $\sqrt{38} \times \sqrt{38}$ and simplify the result.
2. **Recall the property of square roots:** The product of square roots can be combined as
$$\sqrt{a} \times \sqrt{a} = \sqrt{a \times a} = \sqrt{a^2} = a$$
3. **Apply the property:**
$$\sqrt{38} \times \sqrt{38} = \sqrt{38 \times 38} = \sqrt{38^2} = 38$$
4. **Simplify:** Since $38$ is a positive number, the square root squared returns the original number.
**Final answer:**
$$38$$