Question: Solve for , identify any extraneous solutions: $\sqrt{\ } + 12 =$ Correct solution: $x=$ Extraneous solution: $x=$
1. The problem is to solve the equation involving a square root and identify any extraneous solutions.
2. Since the equation is incomplete as given ($\sqrt{\ } + 12 =$), we need the full expression under the square root and the right side to proceed. However, assuming the equation is of the form $\sqrt{x} + 12 = y$ for some $y$, the general approach is:
3. Isolate the square root term: $\sqrt{x} = y - 12$
4. Square both sides to eliminate the square root: $$\left(\sqrt{x}\right)^2 = (y - 12)^2$$
5. Simplify: $$x = (y - 12)^2$$
6. Check for extraneous solutions by substituting back into the original equation because squaring can introduce invalid solutions.
7. Without the exact equation, we cannot find numeric solutions.
Please provide the complete equation to solve for $x$ and identify extraneous solutions.