1. The problem is to find the square roots of the given numbers: 3,721; 5,184; 6,400; 2,704; 7,225; and 8,416. 2. The formula for the square root of a number $x$ is $\sqrt{x}$, which means a number $y$ such that $y^2 = x$. 3. We calculate each square root step-by-step: - $\sqrt{3721}$: Since $61^2 = 3721$, $\sqrt{3721} = 61$. - $\sqrt{5184}$: Since $72^2 = 5184$, $\sqrt{5184} = 72$. - $\sqrt{6400}$: Since $80^2 = 6400$, $\sqrt{6400} = 80$. - $\sqrt{2704}$: Since $52^2 = 2704$, $\sqrt{2704} = 52$. - $\sqrt{7225}$: Since $85^2 = 7225$, $\sqrt{7225} = 85$. - $\sqrt{8416}$: Since $92^2 = 8464$ and $91^2 = 8281$, 8416 is not a perfect square, so we approximate: $\sqrt{8416} \approx 91.7$ (rounded to one decimal place). 4. Final answers: $$\sqrt{3721} = 61$$ $$\sqrt{5184} = 72$$ $$\sqrt{6400} = 80$$ $$\sqrt{2704} = 52$$ $$\sqrt{7225} = 85$$ $$\sqrt{8416} \approx 91.7$$