Question: top-left: 2. ∑_{j=2}^{6} (j^3 - 1)
1. Problem: evaluate $\sum_{j=2}^{6} (j^3-1)$.
2. Use the sum by substituting each value of $j$ from $2$ to $6$.
3. Compute each term:
$$2^3-1=8-1=7$$
$$3^3-1=27-1=26$$
$$4^3-1=64-1=63$$
$$5^3-1=125-1=124$$
$$6^3-1=216-1=215$$
4. Add the results:
$$7+26+63+124+215=435$$
5. Final answer: $435$.