Subjects algebra

Ticket Ratio 2F6E6A

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Question: Yesterday a movie theater showed a new film and sold out all $$200$$ tickets. The ratio of children's tickets to adult tickets was $$2$$ to $$3$$. How many more adult tickets than children's tickets were sold?
1. **State the problem:** We have a total of $$200$$ tickets sold with a ratio of children's tickets to adult tickets as $$2:3$$. We need to find how many more adult tickets than children's tickets were sold. 2. **Set up variables:** Let the number of children's tickets be $$2x$$ and the number of adult tickets be $$3x$$ because the ratio is $$2:3$$. 3. **Write the equation for total tickets:** $$2x + 3x = 200$$ 4. **Simplify the equation:** $$5x = 200$$ 5. **Solve for $$x$$:** $$x = \frac{200}{5}$$ $$x = 40$$ 6. **Find the number of children's tickets:** $$2x = 2 \times 40 = 80$$ 7. **Find the number of adult tickets:** $$3x = 3 \times 40 = 120$$ 8. **Calculate how many more adult tickets than children's tickets were sold:** $$120 - 80 = 40$$ **Final answer:** There were $$40$$ more adult tickets sold than children's tickets.