Turning Point 36Dedd

1. **State the problem:** Find the turning point of the function $$y=(x+2)^2$$. 2. **Recall the formula and concept:** The turning point of a quadratic function in the form $$y=a(x-h)^2+k$$ is at the vertex $$(h,k)$$. 3. **Identify the vertex:** Here, the function is already in vertex form with $$a=1$$, $$h=-2$$, and $$k=0$$. 4. **Interpret the vertex:** The turning point is at $$(-2,0)$$. 5. **Explain:** Since $$a=1>0$$, the parabola opens upwards, so the turning point is a minimum. **Final answer:** The turning point of $$y=(x+2)^2$$ is at $$(-2,0)$$, which is a minimum point.