Subjects algebra

Volume Benda Putar A6C112

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1. **Tentukan volume benda putar yang dibatasi oleh kurva** $y = x^2 + 1$ dan $y = x + 3$ diputar mengelilingi sumbu $x$ sejauh 360°. 2. **Cari titik potong kedua kurva untuk menentukan batas integral:** $$x^2 + 1 = x + 3$$ $$x^2 - x - 2 = 0$$ $$ (x - 2)(x + 1) = 0$$ Jadi, batas integral adalah $x = -1$ sampai $x = 2$. 3. **Gunakan rumus volume benda putar dengan metode washer:** $$V = \pi \int_{a}^{b} \left[ (y_\text{atas})^2 - (y_\text{bawah})^2 \right] dx$$ Di sini, $y_\text{atas} = x + 3$ dan $y_\text{bawah} = x^2 + 1$. 4. **Substitusi fungsi ke dalam integral:** $$V = \pi \int_{-1}^{2} \left[ (x + 3)^2 - (x^2 + 1)^2 \right] dx$$ 5. **Kembangkan kuadrat:** $$(x + 3)^2 = x^2 + 6x + 9$$ $$(x^2 + 1)^2 = x^4 + 2x^2 + 1$$ 6. **Masukkan ke integral:** $$V = \pi \int_{-1}^{2} \left( x^2 + 6x + 9 - x^4 - 2x^2 - 1 \right) dx$$ $$= \pi \int_{-1}^{2} \left( -x^4 - x^2 + 6x + 8 \right) dx$$ 7. **Integralkan setiap suku:** $$\int -x^4 dx = -\frac{x^5}{5}$$ $$\int -x^2 dx = -\frac{x^3}{3}$$ $$\int 6x dx = 3x^2$$ $$\int 8 dx = 8x$$ 8. **Tuliskan integral lengkap:** $$V = \pi \left[ -\frac{x^5}{5} - \frac{x^3}{3} + 3x^2 + 8x \right]_{-1}^{2}$$ 9. **Hitung nilai batas atas ($x=2$):** $$-\frac{2^5}{5} - \frac{2^3}{3} + 3(2^2) + 8(2) = -\frac{32}{5} - \frac{8}{3} + 12 + 16$$ 10. **Hitung nilai batas bawah ($x=-1$):** $$-\frac{(-1)^5}{5} - \frac{(-1)^3}{3} + 3(-1)^2 + 8(-1) = -\frac{-1}{5} - \frac{-1}{3} + 3 - 8 = \frac{1}{5} + \frac{1}{3} - 5$$ 11. **Hitung selisih:** $$\left(-\frac{32}{5} - \frac{8}{3} + 28\right) - \left(\frac{1}{5} + \frac{1}{3} - 5\right) = \left(-\frac{32}{5} - \frac{8}{3} + 28\right) - \left(\frac{1}{5} + \frac{1}{3} - 5\right)$$ 12. **Gabungkan pecahan:** $$-\frac{32}{5} - \frac{8}{3} = -\frac{96}{15} - \frac{40}{15} = -\frac{136}{15}$$ $$\frac{1}{5} + \frac{1}{3} = \frac{3}{15} + \frac{5}{15} = \frac{8}{15}$$ 13. **Hitung total:** $$\left(-\frac{136}{15} + 28\right) - \left(\frac{8}{15} - 5\right) = \left(-\frac{136}{15} + \frac{420}{15}\right) - \left(\frac{8}{15} - \frac{75}{15}\right) = \frac{284}{15} - \left(-\frac{67}{15}\right) = \frac{284}{15} + \frac{67}{15} = \frac{351}{15} = \frac{117}{5}$$ 14. **Jadi volume benda putar adalah:** $$V = \pi \times \frac{117}{5} = \frac{117}{5} \pi$$ **Jawaban akhir:** Volume benda putar adalah $$\boxed{\frac{117}{5} \pi}$$ satuan volume.