Question: Jasmine walks 9 miles in 3 hours, and Mason walks 10 miles in 5 hours.
Whose walking rate is greater, and what is the difference in their rates?
○ Jasmine's rate is greater by 1 mile per hour.
○ Jasmine’s rate is greater by 0.6 miles per hour.
○ Mason’s rate is greater by 1 mile per hour.
○ Mason’s rate is greater by 0.6 miles per hour.
Parker walks to school at a constant rate of 5 yards every 2 seconds.
Which is the unit rate of Parker's walking speed in yards per second?
○ 1 yard per second
○ 1.5 yards per second
○ 2 yards per second
○ 2.5 yards per second
1. **State the problem:**
We need to find the walking rates of Jasmine and Mason in miles per hour and determine whose rate is greater and by how much.
Then, find Parker's unit walking rate in yards per second.
2. **Formula for rate:**
Rate = \frac{Distance}{Time}
3. **Calculate Jasmine's rate:**
$$\text{Jasmine's rate} = \frac{9 \text{ miles}}{3 \text{ hours}} = 3 \text{ miles per hour}$$
4. **Calculate Mason's rate:**
$$\text{Mason's rate} = \frac{10 \text{ miles}}{5 \text{ hours}} = 2 \text{ miles per hour}$$
5. **Compare rates:**
Jasmine's rate is greater.
Difference = $$3 - 2 = 1$$ mile per hour.
6. **Answer for Jasmine and Mason:**
Jasmine's rate is greater by 1 mile per hour.
7. **Calculate Parker's unit rate:**
Given Parker walks 5 yards every 2 seconds.
Unit rate = $$\frac{5 \text{ yards}}{2 \text{ seconds}} = 2.5 \text{ yards per second}$$
8. **Answer for Parker:**
Parker's walking speed is 2.5 yards per second.
**Final answers:**
- Jasmine's rate is greater by 1 mile per hour.
- Parker's unit walking speed is 2.5 yards per second.