Subjects algebra

Width From Perimeter 3F8C4F

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Question: Express the formula $P = 2l + 2w$ in terms of the width, $w$. Use the formula to find the width when the perimeter is $70$ and the length is $22$. ○ $w = \frac{P - l}{2}$; $w = 24$ ○ $w = \frac{P}{2} - l$; $w = 13$ ○ $w = P - 2l$; $w = 26$ ○ $w = \frac{P - 2l}{2}$; $w = 9$
1. **State the problem:** We are given the perimeter formula for a rectangle: $$P = 2l + 2w$$ We need to express $w$ in terms of $P$ and $l$, then find $w$ when $P = 70$ and $l = 22$. 2. **Rearrange the formula to solve for $w$:** Start with: $$P = 2l + 2w$$ Subtract $2l$ from both sides: $$P - 2l = 2w$$ Divide both sides by 2: $$\frac{P - 2l}{\cancel{2}} = \frac{2w}{\cancel{2}}$$ which simplifies to: $$w = \frac{P - 2l}{2}$$ 3. **Substitute the given values $P=70$ and $l=22$ into the formula:** $$w = \frac{70 - 2 \times 22}{2}$$ Calculate the numerator: $$70 - 44 = 26$$ So: $$w = \frac{26}{2}$$ Divide: $$w = 13$$ 4. **Conclusion:** The correct formula for $w$ is: $$w = \frac{P - 2l}{2}$$ and the width when $P=70$ and $l=22$ is: $$w = 13$$ This matches the second option: ○ $w = \frac{P}{2} - l$; $w = 13$ Note that $\frac{P}{2} - l = \frac{70}{2} - 22 = 35 - 22 = 13$, which is algebraically equivalent to $\frac{P - 2l}{2}$. Hence, the correct answer is the second option.