1. **State the problem:** Find the x-intercept and y-intercept of the linear equation $$-3x + 2y = 6$$. 2. **Recall the intercept definitions:** - The x-intercept is where the graph crosses the x-axis, so $$y=0$$. - The y-intercept is where the graph crosses the y-axis, so $$x=0$$. 3. **Find the x-intercept:** Set $$y=0$$ in the equation: $$-3x + 2(0) = 6 \implies -3x = 6 \implies x = \frac{6}{-3} = -2$$ So the x-intercept is $$(-2, 0)$$. 4. **Find the y-intercept:** Set $$x=0$$ in the equation: $$-3(0) + 2y = 6 \implies 2y = 6 \implies y = \frac{6}{2} = 3$$ So the y-intercept is $$(0, 3)$$. 5. **Summary:** - x-intercept: $$(-2, 0)$$ - y-intercept: $$(0, 3)$$ These points can be plotted to graph the line.