Question: What are the x-intercepts of $g(x) = -2|x + 1| + 4$?
1. **State the problem:** Find the x-intercepts of the function $$g(x) = -2|x + 1| + 4$$. The x-intercepts occur where $$g(x) = 0$$.
2. **Set the function equal to zero:**
$$0 = -2|x + 1| + 4$$
3. **Isolate the absolute value term:**
$$-2|x + 1| = -4$$
Divide both sides by $$-2$$:
$$|x + 1| = \cancel{-2}\frac{-4}{\cancel{-2}} = 2$$
4. **Solve the absolute value equation:**
$$|x + 1| = 2$$ means
$$x + 1 = 2$$ or $$x + 1 = -2$$
5. **Find the solutions:**
- For $$x + 1 = 2$$:
$$x = 2 - 1 = 1$$
- For $$x + 1 = -2$$:
$$x = -2 - 1 = -3$$
6. **Conclusion:** The x-intercepts are $$x = -3$$ and $$x = 1$$.
Therefore, the correct answer is Option B: $$x = -3$$ and $$x = 1$$.