Question: y intercept of $x(x-1)(x+4)$
1. **State the problem:** Find the $y$-intercept of the function $$y = x(x-1)(x+4)$$.
2. **Recall the rule for $y$-intercept:** The $y$-intercept occurs where $x=0$. To find it, substitute $x=0$ into the function.
3. **Substitute $x=0$:**
$$y = 0(0-1)(0+4)$$
4. **Simplify:**
$$y = 0 \times (-1) \times 4 = 0$$
5. **Conclusion:** The $y$-intercept is at the point $(0,0)$.
This means the graph crosses the $y$-axis at the origin.