Question: 5.) (4m^3n^3 / 8m^2n^2)^0 = 1
6.) (3^3 x^2 y^2 / 6xy^4)^-2 =
A 7.) [(m-1)^0 / m^3 n^3]^4 =
A 8.) (b^(n-3))^2 / (b^(n+2))^2 =
1. **State the problem:** Simplify the expression $$\left(\frac{4m^3n^3}{8m^2n^2}\right)^0$$ and verify the result.
2. **Recall the zero exponent rule:** Any nonzero expression raised to the power of zero equals 1, i.e., $$a^0 = 1$$ for $$a \neq 0$$.
3. **Apply the rule:** Since the base $$\frac{4m^3n^3}{8m^2n^2}$$ is nonzero (assuming variables are nonzero), raising it to the zero power gives:
$$\left(\frac{4m^3n^3}{8m^2n^2}\right)^0 = 1$$
4. **No further simplification needed.**
**Final answer:** $$1$$