🧮 algebra
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Vertical Line
1. The problem asks for the equation of the line passing through the points $(-4,5)$ and $(-4,-2)$.
2. First, calculate the slope $m$ using the formula $$m=\frac{y_2 - y_1}{x_2 - x
Line Equation
1. **State the problem:** Find the equation of the line passing through the points $(5,-6)$ and $(-5,-4)$.
2. **Calculate the slope $m$:**
Vertical Line
1. **State the problem:** Find the equation of the line passing through the points $(8,3)$ and $(8,-2)$.
2. **Calculate the slope:** The slope $m$ is given by $$m = \frac{y_2 - y_1
Vertical Line
1. **State the problem:** Find the equation of the line passing through the points $(2,-3)$ and $(2,6)$.
2. **Calculate the slope:** The slope $m$ is given by $$m=\frac{y_2 - y_1}{
Line Equation
1. **State the problem:** Find the equation of the line passing through the points (-8, -3), (-1, 0), (5, 1), and (10, 2) in slope-intercept form $y=mx+b$.
2. **Calculate the slope
Line Equation
1. **State the problem:** Find the equation of the line passing through the points $(4,-7)$ and $(8,-6)$.
2. **Calculate the slope $m$:**
Line Equation
1. **State the problem:** Find the equation of the line passing through the points $(-3,-4)$ and $(-4,-6)$.\n\n2. **Calculate the slope $m$:** The slope formula is $$m=\frac{y_2 -
Line Equation
1. **State the problem:** Find the equation of the line passing through the points $(6,0)$ and $(3,4)$.
2. **Calculate the slope $m$:**
Line Equation
1. **State the problem:** Find the equation of the line passing through the points $(3,6)$ and $(1,-2)$.
2. **Calculate the slope $m$:**
Line Equation
1. **State the problem:** Find the equation of the line passing through the points $(6,1)$ and $(3,3)$.
2. **Calculate the slope $m$:**
Sum Fractions
1. **State the problem:** Express $\frac{3}{4} + \frac{5 - x}{6x}$ as a single fraction in simplest terms.
2. **Find a common denominator:** The denominators are 4 and $6x$. The le
Factorisation Expression
1. Énonçons le problème : factoriser l'expression $ (x-5) + (5-x)^2 $.\n\n2. Observons que $5-x = -(x-5)$, donc $ (5-x)^2 = (-(x-5))^2 = (x-5)^2 $.\n\n3. L'expression devient donc
Solve Linear Systems
1. **State the problem:** Solve the system of equations for Exercises 5 to 18.
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Parabola Line
1. **State the problem:** We have a parabola $g(x) = ax^{2} + q$ opening downwards with $x$-intercepts $R$ and $S(2,0)$, and $y$-intercept $T(0,8)$. A line $f(x) = mx + c$ passes t
Parabola Line Intercepts
1. **State the problem:** We have a parabola $g(x) = ax^2 + q$ with x-intercepts $R(x_R,0)$ and $S(2,0)$, and y-intercept $T(0,8)$. A line $f(x) = mx + c$ passes through points $R$
Function Analysis
1. **State the problem:** We analyze the functions $f$, $g$, and $h$ based on the graph and given points.
2. **Range of $g$:** The range is the set of all $y$-values that $g$ attai
Quadratic Linear
1. **State the problem:** We have a quadratic function $g(x) = ax^2 + q$ with x-intercepts $R$ and $S(2,0)$, and y-intercept $T(0,8)$. A linear function $f(x) = mx + c$ passes thro
Solve Linear
1. The problem is to solve the equation $$2x + 3 = 7$$ for $x$.
2. Start by isolating the variable term $2x$ on one side. Subtract 3 from both sides:
Solve Quadratic
1. Stating the problem: Solve the equation $x^2 + 1 = 0$ for $x$.
2. Isolate the term with $x$: Subtract 1 from both sides to get
Solve Quadratic
1. The problem is to solve the equation $x^2 + 1 = 0$ for $x$.
2. Start by isolating $x^2$: subtract 1 from both sides to get
Solve Quadratic
1. Stating the problem: Solve the equation $x^2 + 1 = 0$ for $x$.
2. Isolate the term with $x$: Subtract 1 from both sides to get