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🧮 algebra

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Square Root
1. We are asked to simplify the expression \(\sqrt{x}\). 2. The square root function \(\sqrt{x}\) represents the principal (non-negative) number which when squared gives \(x\).
Series Sum
1. Stating the problem: Simplify the series $5 - 10 + 15 - 20 + 25 - 30 + \ldots + 95 - 100$. 2. Notice the pattern: the terms alternate between adding and subtracting multiples of
Square Product
1. State the problem: Simplify and calculate the value of the expression $$(0-6)^2(9-0)^2(5-12)^2$$. 2. Simplify inside the parentheses:
Simple Interest
1. āĻĒā§āϰāĻļā§āύāϟāĻŋ āĻšāϞ⧋: āĻŦāĻžāĻ°ā§āώāĻŋāĻ• āĻ•āϤ āĻšāĻžāϰ āϏ⧁āĻĻ⧇ āϕ⧋āύ āĻŽā§‚āϞāϧāύ ā§§ā§Ļ āĻŦāĻ›āϰ⧇āϰ āĻŽā§āύāĻžāĻĢāĻž āφāϏāϞ⧇ āϤāĻŋāύ āϗ⧁āĻŖ āĻšāĻŦ⧇? 2. āĻ…āĻ°ā§āĻĨāĻžā§Ž ā§§ā§Ļ āĻŦāĻ›āϰ⧇ āĻŽā§‚āϞāϧāύ $P$ āĻĨ⧇āϕ⧇ $3P$ āĻšāĻŦ⧇āĨ¤
Solve Rational Equation
1. **Stating the problem:** We need to solve the equation $$\frac{1200}{x} - \frac{1200}{x+2} = 20$$ and interpret the geometry of the rectangle with dimensions labeled as describe
Sum Difference
1. Stating the problem: Find two numbers $x$ and $y$ such that their sum is 12 and their difference is 4. 2. Write equations from the problem:
Percentage Calculation
1. āĻĒā§āϰāĻļā§āύāϟāĻŋ āĻšāϞ, "āωāĻ¤ā§āϤāϰ 20% āĻšāĻŦ⧇"āĨ¤ āĻ…āĻ°ā§āĻĨāĻžā§Ž, āφāĻŽāϰāĻž āϜāĻžāύāϤ⧇ āϚāĻžāχ āĻāĻ•āϟāĻŋ āϏāĻ‚āĻ–ā§āϝāĻžāϰ 20% āĻ•āϤ āĻšā§ŸāĨ¤ 2. āϕ⧋āύ⧋ āϏāĻ‚āĻ–ā§āϝāĻžāϰ 20% āĻĒāĻžāĻ“ā§ŸāĻž āϝāĻžā§Ÿ āϏāĻ‚āĻ–ā§āϝāĻž × 20/100 āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ•āϰ⧇āĨ¤
Percent Value
1. āϏāĻŽāĻ¸ā§āϝāĻž: āĻŦā§āϝāĻŦāĻšāĻžāϰāĻ•āĻžāϰ⧀āϰ āϧāĻžāϰāĻŖāĻž āϝ⧇ āωāĻ¤ā§āϤāϰāϟāĻŋ 20% āĻšāĻŦ⧇ āϤāĻž āϝāĻžāϚāĻžāχ āĻ•āϰāĻžāĨ¤ 2. āϝāĻĻāĻŋ āϕ⧋āύāĻ“ āύāĻŋāĻ°ā§āĻĻāĻŋāĻˇā§āϟ āĻĒā§āϰāĻļā§āύ āĻŦāĻž āĻ—āĻŖāύāĻžāϰ āĻĒā§āϰāϏāĻ™ā§āĻ— āĻĨāĻžāϕ⧇, āϤāĻž āĻ¸ā§āĻĒāĻˇā§āϟ āĻ•āϰāϤ⧇ āĻšāĻŦ⧇āĨ¤
Compound Interest Rate
1. āĻĒā§āϰāĻļā§āύāϟāĻŋāϤ⧇ āĻŦāϞāĻž āĻšāϝāĻŧ⧇āϛ⧇, āĻāĻ•āϟāĻŋ āĻ…āĻ°ā§āĻĨ⧇āϰ āĻŦāĻžāĻ°ā§āώāĻŋāĻ• āϏ⧁āĻĻ⧇āϰ āĻšāĻžāϰ āĻ•āϤ āĻšāϞ⧇ ā§§ā§Ļ āĻŦāĻ›āϰ⧇ āϏ⧇āϟāĻžāϰ āĻŽāĻžāύ āϤāĻŋāύ āϗ⧁āĻŖ āĻšāϝāĻŧāĨ¤ 2. āĻāĻ–āĻžāύ⧇ āĻŽā§‚āϞāϧāύ $P$, āϏāĻŽāϝāĻŧ $t=10$ āĻŦāĻ›āϰ āĻāĻŦāĻ‚ āĻĒāϰāĻŋāĻŽāĻžāĻŖ $A=3P$ (ā§Š āϗ⧁āĻŖ) āĻ—āĻŖāύāĻž āĻ•āϰāϤ⧇ āĻšāĻŦ⧇ āĻŦāĻžāĻ°ā§āώāĻŋāĻ• āϏ⧁
Simplify Radical Division
1. The problem is to simplify the expression \( \frac{4}{\sqrt{5} - \sqrt{2} - \sqrt{6}} \).\n\n2. First, identify the denominator: \( \sqrt{5} - \sqrt{2} - \sqrt{6} \). The goal i
Simplify Fraction
1. The problem asks to simplify the expression $$\frac{\frac{y}{\sqrt{5}} - \sqrt{2} - \sqrt{6}}{\sqrt{5} - \sqrt{2} - \sqrt{6}}$$ and express it clearly. 2. First, rewrite the num
Cyclist Time
1. The problem states a cyclist travels 20 km at an average speed of $x$ km/h. 2. (a) The time taken for this journey is distance divided by speed, which is $$\frac{20}{x}$$ hours.
Simplification Racines
1. Énonçons le problème : Simplifier l'expression $$\frac{y}{\sqrt{y^{2}-16}} - \frac{x}{\sqrt{x^{2}-16}}$$ et comparer avec $$\frac{2y}{\sqrt{y^{2}-16}} - \frac{2x}{\sqrt{x^{2}-16
Logarithm Properties
1. **Problem a:** Write the scientific form of 0.006237 and find the characteristic of its logarithm. - First, write 0.006237 in scientific notation. Move the decimal 3 places righ
Solve Quadratics
1. Stating the problem: Solve the system:
Function Inverses
1. The problem states two functions. First, \( f(x) = \sqrt{x+1} - 1 \) with its inverse \( g(x) = x+1 \). 2. The domain of \( f \) is \( x \geq -1 \) because the expression under
Fraction Expression
1. State the problem: Simplify the expression $$-\frac{7}{4} + \frac{7}{16} \times \frac{1}{8} \times 384 \times \frac{3}{28}$$. 2. First, calculate the product part $$\frac{7}{16}
Expression Simplification
1. Stating the problem: Simplify the expression $$\frac{3}{2} - \frac{153}{4} \times 4 \left(4 - \frac{503}{126}\right)$$ and give the answer as an integer or simplified fraction.
Oppose A
1. Énonçons le problème : Trouver l'opposÊ de $a$ dans la fraction $\frac{16}{9}$.\n\n2. Rappelons que l'opposÊ d'un nombre $a$ est $-a$.\n\n3. Ici, la fraction $\frac{16}{9}$ repr
Monthly Tea Income
1. ā¤¸ā¤Žā¤¸āĨā¤¯ā¤ž: ā¤ĻāĨ‹ ā¤ĩāĨā¤¯ā¤•āĨā¤¤ā¤ŋ ā¤šā¤žā¤¯ ā¤ŦāĨ‡ā¤šā¤¤āĨ‡ ā¤šāĨˆā¤‚āĨ¤ ā¤Ēā¤šā¤˛ā¤ž ā¤ĩāĨā¤¯ā¤•āĨā¤¤ā¤ŋ ā¤¸ā¤žā¤˛ā¤žā¤¨ā¤ž 150 ⤕āĨā¤ĩā¤ŋā¤‚ā¤Ÿā¤˛ ā¤šā¤žā¤¯ 60 ⤰āĨā¤Ēā¤ ā¤ĒāĨā¤°ā¤¤ā¤ŋ ⤕āĨā¤ĩā¤ŋā¤‚ā¤Ÿā¤˛ ā¤ŦāĨ‡ā¤šā¤¤ā¤ž ā¤šāĨˆāĨ¤ ā¤ĻāĨ‚ā¤¸ā¤°ā¤ž ā¤ĩāĨā¤¯ā¤•āĨā¤¤ā¤ŋ 100 ⤕āĨā¤ĩā¤ŋā¤‚ā¤Ÿā¤˛ ā¤šā¤žā¤¯ 300 ⤰āĨā¤Ēā¤ ā¤ĒāĨā¤°ā¤¤ā¤ŋ ⤕āĨā¤ĩā¤ŋā¤‚ā¤Ÿā¤˛ ā¤ŦāĨ‡ā¤šā¤¤ā¤ž ā¤šāĨˆāĨ¤ ā¤šā¤ŽāĨ‡ā¤‚ ā¤ĻāĨ‚ā¤¸ā¤°ā¤ž ā¤ĩ
Solving Exponent Equation
1. We are given the equation $x^2 \sqrt{x} = 3$. 2. Recall that $\sqrt{x} = x^{1/2}$.