Subtract Mixed Numbers 52Cbfa

1. **State the problem:** We need to subtract the mixed numbers $6 \frac{11}{16}$ and $3 \frac{5}{16}$. 2. **Convert mixed numbers to improper fractions:** $$6 \frac{11}{16} = \frac{6 \times 16 + 11}{16} = \frac{96 + 11}{16} = \frac{107}{16}$$ $$3 \frac{5}{16} = \frac{3 \times 16 + 5}{16} = \frac{48 + 5}{16} = \frac{53}{16}$$ 3. **Subtract the improper fractions:** Since denominators are the same, subtract numerators: $$\frac{107}{16} - \frac{53}{16} = \frac{107 - 53}{16} = \frac{54}{16}$$ 4. **Simplify the fraction:** Find the greatest common divisor (GCD) of 54 and 16, which is 2. $$\frac{54}{16} = \frac{\cancel{2} \times 27}{\cancel{2} \times 8} = \frac{27}{8}$$ 5. **Convert back to mixed number:** Divide 27 by 8: $$27 \div 8 = 3 \text{ remainder } 3$$ So, $$\frac{27}{8} = 3 \frac{3}{8}$$ **Final answer:** $$6 \frac{11}{16} - 3 \frac{5}{16} = 3 \frac{3}{8}$$