Question: There is $\frac{6}{5}$ cups of water in a measuring cup. How much would be left if Cameron poured out $\frac{1}{3}$ of a cup? Write your answer as a fraction, whole, or mixed number in simplest form.
1. **State the problem:** We start with $\frac{6}{5}$ cups of water and Cameron pours out $\frac{1}{3}$ cup. We need to find how much water is left.
2. **Formula:** The amount left is the initial amount minus the amount poured out:
$$\text{Amount left} = \frac{6}{5} - \frac{1}{3}$$
3. **Find a common denominator:** The denominators are 5 and 3. The least common denominator (LCD) is 15.
4. **Convert fractions:**
$$\frac{6}{5} = \frac{6 \times 3}{5 \times 3} = \frac{18}{15}$$
$$\frac{1}{3} = \frac{1 \times 5}{3 \times 5} = \frac{5}{15}$$
5. **Subtract the fractions:**
$$\frac{18}{15} - \frac{5}{15} = \frac{18 - 5}{15} = \frac{13}{15}$$
6. **Simplify if possible:** $\frac{13}{15}$ cannot be simplified further because 13 and 15 have no common factors other than 1.
7. **Final answer:**
$$\boxed{\frac{13}{15}}$$
So, after pouring out $\frac{1}{3}$ cup, $\frac{13}{15}$ cups of water remain.