Question: I need to find the critical points
1. **State the problem:** We need to find the critical points of a function. Critical points occur where the derivative of the function is zero or undefined.
2. **Formula and rules:** The critical points are found by solving $$f'(x) = 0$$ or where $$f'(x)$$ does not exist.
3. **Steps to find critical points:**
- Find the derivative $$f'(x)$$ of the given function $$f(x)$$.
- Solve the equation $$f'(x) = 0$$ to find potential critical points.
- Check where $$f'(x)$$ is undefined.
4. **Example:** Suppose $$f(x) = x^3 - 3x^2 + 4$$.
- Compute derivative: $$f'(x) = 3x^2 - 6x$$.
- Set derivative to zero: $$3x^2 - 6x = 0$$.
- Factor: $$3x(x - 2) = 0$$.
- Solve: $$x = 0$$ or $$x = 2$$.
- Check if derivative undefined anywhere: derivative is a polynomial, so defined everywhere.
5. **Conclusion:** The critical points are at $$x = 0$$ and $$x = 2$$.
You can apply this method to any differentiable function to find its critical points.