Integral Inverse Tangent B4753D

1. **State the problem:** We need to find the integral $$\int \frac{1}{1+x^2} \, dx$$. 2. **Recall the formula:** The integral of $$\frac{1}{1+x^2}$$ with respect to $$x$$ is a standard integral that equals $$\arctan(x) + C$$, where $$C$$ is the constant of integration. 3. **Explanation:** This is because the derivative of $$\arctan(x)$$ is $$\frac{1}{1+x^2}$$. 4. **Write the solution:** Therefore, $$\int \frac{1}{1+x^2} \, dx = \arctan(x) + C$$. 5. **Summary:** The integral of $$\frac{1}{1+x^2}$$ is the inverse tangent function plus a constant.