Limit E3 Over 8 X A44542

1. **State the problem:** We want to find the limit $$\lim_{x \to 8^-} \frac{e^3}{8 - x}$$. 2. **Understand the expression:** The numerator is a constant $$e^3$$. The denominator $$8 - x$$ approaches zero as $$x$$ approaches 8 from the left (values less than 8). 3. **Analyze the denominator behavior:** As $$x \to 8^-$$, $$8 - x$$ is a small positive number because $$x$$ is slightly less than 8. 4. **Evaluate the limit:** Since the numerator $$e^3$$ is positive and constant, and the denominator approaches zero from the positive side, the fraction $$\frac{e^3}{8 - x}$$ grows without bound positively. 5. **Conclusion:** Therefore, $$\lim_{x \to 8^-} \frac{e^3}{8 - x} = +\infty$$. This means the function increases without bound as $$x$$ approaches 8 from the left.