Question: If $f(x)$ is a polynomial function of odd degree and
$$\lim_{x \to \infty} f(x) = -\infty,$$
then evaluate the following limit.
Provide your answer below:
$$\lim_{x \to -\infty} f(x) =$$
1. **Problem Statement:**
We are given a polynomial function $f(x)$ of odd degree such that
$$\lim_{x \to \infty} f(x) = -\infty.$$
We need to find
$$\lim_{x \to -\infty} f(x).$$
2. **Recall the behavior of odd degree polynomials:**
- A polynomial of odd degree has the general form:
$$f(x) = a_n x^n + \dots + a_1 x + a_0,$$
where $n$ is odd and $a_n \neq 0$.
- The end behavior of $f(x)$ is dominated by the leading term $a_n x^n$.
- For odd $n$, as $x \to \infty$, $a_n x^n$ tends to $\infty$ if $a_n > 0$ and to $-\infty$ if $a_n < 0$.
- As $x \to -\infty$, $a_n x^n$ tends to $-\infty$ if $a_n > 0$ and to $\infty$ if $a_n < 0$.
3. **Given:**
$$\lim_{x \to \infty} f(x) = -\infty,$$
which means the leading coefficient $a_n$ is negative.
4. **Therefore, as $x \to -\infty$:**
Since $n$ is odd and $a_n < 0$, the leading term behaves as
$$a_n (-\infty)^n = a_n \cdot (-\infty) = \infty,$$
because an odd power preserves the sign of $x$, and multiplying by negative $a_n$ flips the sign.
5. **Conclusion:**
$$\lim_{x \to -\infty} f(x) = \infty.$$