Question: Find the first partial derivatives of the following function.
h(x,y) = (5 + 3y)^x
1. **State the problem:** Find the first partial derivatives $\frac{\partial h}{\partial x}$ and $\frac{\partial h}{\partial y}$ of the function $$h(x,y) = (5 + 3y)^x$$.
2. **Recall the formula:** For a function of the form $$h(x,y) = f(y)^x$$, the partial derivatives are found using the chain rule and logarithmic differentiation.
3. **Partial derivative with respect to $x$:** Treat $y$ as constant.
$$\frac{\partial h}{\partial x} = (5 + 3y)^x \ln(5 + 3y)$$
4. **Partial derivative with respect to $y$:** Treat $x$ as constant.
Use the chain rule:
$$\frac{\partial h}{\partial y} = x (5 + 3y)^{x-1} \cdot \frac{\partial}{\partial y}(5 + 3y) = x (5 + 3y)^{x-1} \cdot 3$$
5. **Final answers:**
$$\frac{\partial h}{\partial x} = (5 + 3y)^x \ln(5 + 3y)$$
$$\frac{\partial h}{\partial y} = 3x (5 + 3y)^{x-1}$$