Subjects calculus

Second Derivative Constant 4Acedd

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Question: isnt the second derivative of $\phi(x) = \frac{1}{4} e^2$ ?
1. **State the problem:** We want to find the second derivative of the function $$\phi(x) = \frac{1}{4} e^2$$. 2. **Analyze the function:** Note that $e$ is Euler's number (approximately 2.71828), and $e^2$ is a constant since it does not depend on $x$. 3. **Rewrite the function:** Since $\frac{1}{4} e^2$ is a constant, we can write: $$\phi(x) = C$$ where $$C = \frac{1}{4} e^2$$. 4. **Recall derivative rules:** The derivative of a constant function is zero: $$\frac{d}{dx} C = 0$$. 5. **Calculate the first derivative:** $$\phi'(x) = 0$$. 6. **Calculate the second derivative:** $$\phi''(x) = \frac{d}{dx} \phi'(x) = \frac{d}{dx} 0 = 0$$. **Final answer:** The second derivative of $$\phi(x) = \frac{1}{4} e^2$$ is $$0$$.