Question: User: limits involving trigonometric functions
1. **Problem Statement:** Find the limit of a function involving trigonometric expressions as the variable approaches a certain value.
2. **General Formula and Rules:**
- Use the standard limit \(\lim_{x \to 0} \frac{\sin x}{x} = 1\).
- For limits involving \(\cos x\), recall \(\lim_{x \to 0} \frac{1 - \cos x}{x^2} = \frac{1}{2}\).
- Apply algebraic manipulation and trigonometric identities to simplify the expression.
3. **Example:** Suppose we want to find \(\lim_{x \to 0} \frac{\sin 3x}{x}\).
4. **Step-by-step solution:**
- Rewrite the limit as \(\lim_{x \to 0} \frac{\sin 3x}{3x} \cdot 3\).
- Using the standard limit, \(\lim_{x \to 0} \frac{\sin 3x}{3x} = 1\).
- Therefore, the limit is \(1 \times 3 = 3\).
5. **Explanation:**
- We used the substitution \(u = 3x\) to transform the limit into a known standard form.
- The factor outside the sine function scales the limit accordingly.
6. **Final answer:** \(3\).