Subjects chemistry

Nitrogen Bonding Ce64B0

Step-by-step solutions with LaTeX - clean, fast, and student-friendly.

Use the AI math solver

Question: Sort the following to identify the bonding patterns of a neutral nitrogen atom. Bonding pattern (6 items) (Drag and drop or use the dropdown to move cards into the appropriate categories below) top-left: N with one single bond to the left, one double bond to the right, two lone pairs above and below. top-right: N with one lone pair above, one single bond to the left, one double bond to the right. center: N with one lone pair above, one lone pair below, one single bond to the left, one single bond to the right, and one single bond downward. bottom-left: N with two single bonds left and right, one single bond downward, and one lone pair above. bottom-right: N with one lone pair above, one lone pair below, one single bond to the left, and one single bond to the right.
1. **State the problem:** We need to identify the bonding patterns of a neutral nitrogen atom from the given descriptions. 2. **Recall nitrogen's valence electrons and bonding rules:** Nitrogen has 5 valence electrons. In a neutral state, it typically forms 3 bonds and has 1 lone pair to complete its octet. 3. **Analyze each pattern:** - **Top-left:** N with 1 single bond (1 electron), 1 double bond (2 electrons), and 2 lone pairs (4 electrons). Total electrons around N = $1 + 2 + 4 = 7$ electrons, which is 3.5 pairs. This exceeds typical bonding for neutral N and suggests a charged or excited state. - **Top-right:** N with 1 lone pair (2 electrons), 1 single bond (1 electron), 1 double bond (2 electrons). Total = $2 + 1 + 2 = 5$ electrons, which matches nitrogen's valence electrons. This is a valid bonding pattern for neutral N. - **Center:** N with 2 lone pairs (4 electrons), 3 single bonds (3 electrons). Total = $4 + 3 = 7$ electrons, which is more than 5 valence electrons, unlikely for neutral N. - **Bottom-left:** N with 1 lone pair (2 electrons), 3 single bonds (3 electrons). Total = $2 + 3 = 5$ electrons, valid for neutral N. - **Bottom-right:** N with 2 lone pairs (4 electrons), 2 single bonds (2 electrons). Total = $4 + 2 = 6$ electrons, more than 5 valence electrons, unlikely for neutral N. 4. **Conclusion:** The valid bonding patterns for a neutral nitrogen atom are those with a total of 5 valence electrons around N, i.e., top-right and bottom-left. **Final answer:** - Neutral nitrogen bonding patterns: top-right and bottom-left.