Question: To help with her retirement savings, Jane has decided to invest. Assuming an interest rate of 3.58% compounded daily, how much would she have to invest to have $148,700 after 16 years?
1. **State the problem:**
Jane wants to know the present value (initial investment) needed to have $148,700 after 16 years with an interest rate of 3.58% compounded daily.
2. **Formula used:**
The compound interest formula for future value is:
$$ A = P \left(1 + \frac{r}{n}\right)^{nt} $$
where:
- $A$ is the amount of money accumulated after $t$ years, including interest.
- $P$ is the principal (the initial amount to find).
- $r$ is the annual interest rate (decimal).
- $n$ is the number of times interest is compounded per year.
- $t$ is the time the money is invested for in years.
3. **Given values:**
- $A = 148700$
- $r = 3.58\% = 0.0358$
- $n = 365$ (compounded daily)
- $t = 16$
4. **Rearrange formula to solve for $P$:**
$$ P = \frac{A}{\left(1 + \frac{r}{n}\right)^{nt}} $$
5. **Calculate the denominator:**
$$ 1 + \frac{0.0358}{365} = 1 + 0.00009808219 = 1.00009808219 $$
6. **Calculate the exponent:**
$$ nt = 365 \times 16 = 5840 $$
7. **Calculate the compound factor:**
$$ \left(1.00009808219\right)^{5840} $$
Using a calculator:
$$ \approx 1.747422 $$
8. **Calculate present value $P$:**
$$ P = \frac{148700}{1.747422} \approx 85088.68 $$
9. **Round to nearest dollar:**
$$ P \approx 85089 $$
**Answer:** Jane needs to invest approximately $85089 now to have $148700 after 16 years at 3.58% interest compounded daily.