Question: use homogenous diffferential equations
1. **Problem Statement:** Solve a homogeneous differential equation.
2. **Definition:** A first-order differential equation is homogeneous if it can be written as $$\frac{dy}{dx} = F\left(\frac{y}{x}\right)$$ or equivalently if both numerator and denominator of the right side are homogeneous functions of the same degree.
3. **Method:** Use substitution $$v = \frac{y}{x}$$ which implies $$y = vx$$ and $$\frac{dy}{dx} = v + x\frac{dv}{dx}$$.
4. **Rewrite the equation:** Substitute into the original equation to get an equation in terms of $$v$$ and $$x$$:
$$v + x\frac{dv}{dx} = F(v)$$
5. **Isolate $$\frac{dv}{dx}$$:**
$$x\frac{dv}{dx} = F(v) - v$$
6. **Separate variables:**
$$\frac{dv}{F(v) - v} = \frac{dx}{x}$$
7. **Integrate both sides:**
$$\int \frac{1}{F(v) - v} dv = \int \frac{1}{x} dx$$
8. **Solve the integrals:** The right side integrates to $$\ln|x| + C$$. The left side depends on the form of $$F(v)$$.
9. **Back-substitute:** After integration, replace $$v = \frac{y}{x}$$ to express the solution in terms of $$x$$ and $$y$$.
This method transforms the homogeneous differential equation into a separable one, which can be solved by integration.
**Final answer:** The general solution is given implicitly by
$$\int \frac{1}{F(v) - v} dv = \ln|x| + C$$ with $$v = \frac{y}{x}$$.