Question: User: George secured an adjustable-rate mortgage (ARM) loan to help finance the purchase of his home 5 years ago. The amount of the loan was $200,000 for a term of 30 years, with interest at the rate of 8%/year compounded monthly. Currently, the interest rate for his ARM is 5.5%/year compounded monthly, and George's monthly payments are due to be reset. What will be the new monthly payment? (Round your answer to the nearest cent.)
1. **State the problem:**
George took a $200,000 loan for 30 years at 8% annual interest compounded monthly. After 5 years, the interest rate changes to 5.5% compounded monthly, and we need to find the new monthly payment.
2. **Identify the formulas:**
The monthly payment for a loan is given by the amortization formula:
$$ M = P \frac{r(1+r)^n}{(1+r)^n - 1} $$
where:
- $M$ is the monthly payment,
- $P$ is the loan principal,
- $r$ is the monthly interest rate (annual rate divided by 12),
- $n$ is the total number of monthly payments.
3. **Calculate the remaining loan balance after 5 years at the original rate:**
- Original monthly interest rate: $r_1 = \frac{8\%}{12} = \frac{0.08}{12} = 0.0066667$
- Total payments originally: $n = 30 \times 12 = 360$
- Payments made: $5 \times 12 = 60$
First, calculate the original monthly payment $M_1$:
$$ M_1 = 200000 \times \frac{0.0066667(1+0.0066667)^{360}}{(1+0.0066667)^{360} - 1} $$
Calculate powers:
$$ (1+0.0066667)^{360} = (1.0066667)^{360} \approx 10.935 $$
So,
$$ M_1 = 200000 \times \frac{0.0066667 \times 10.935}{10.935 - 1} = 200000 \times \frac{0.0729}{9.935} = 200000 \times 0.00734 = 1468.72 $$
4. **Calculate the remaining balance after 60 payments:**
The remaining balance $B$ after $k$ payments is:
$$ B = P (1+r)^k - M \frac{(1+r)^k - 1}{r} $$
Substitute values:
$$ B = 200000 (1.0066667)^{60} - 1468.72 \times \frac{(1.0066667)^{60} - 1}{0.0066667} $$
Calculate powers:
$$ (1.0066667)^{60} \approx 1.489 $$
Calculate numerator:
$$ 1.489 - 1 = 0.489 $$
Calculate fraction:
$$ \frac{0.489}{0.0066667} = 73.35 $$
Calculate balance:
$$ B = 200000 \times 1.489 - 1468.72 \times 73.35 = 297800 - 107700 = 190100 $$
5. **Calculate new monthly payment with new interest rate and remaining term:**
- New monthly interest rate: $r_2 = \frac{5.5\%}{12} = \frac{0.055}{12} = 0.0045833$
- Remaining term: $30 - 5 = 25$ years, so $n_2 = 25 \times 12 = 300$ months
Use amortization formula with $P = 190100$, $r = 0.0045833$, $n = 300$:
$$ M_2 = 190100 \times \frac{0.0045833 (1+0.0045833)^{300}}{(1+0.0045833)^{300} - 1} $$
Calculate powers:
$$ (1.0045833)^{300} \approx 3.946 $$
Calculate numerator:
$$ 0.0045833 \times 3.946 = 0.01808 $$
Calculate denominator:
$$ 3.946 - 1 = 2.946 $$
Calculate fraction:
$$ \frac{0.01808}{2.946} = 0.006136 $$
Calculate new monthly payment:
$$ M_2 = 190100 \times 0.006136 = 1166.68 $$
6. **Final answer:**
The new monthly payment after the interest rate reset is approximately **$1166.68**.