Question: top-left: Nishi invests $2700 at 6% interest per year.
top-left: Work out how much she will have altogether after:
top-left: 2 years $ [ ]
top-left: 4 years $ [ ]
top-left: 6 years $ [ ]
top-left: 10 years $ [ ]
top-left: [2]
top-left: [2]
top-left: [2]
top-left: [2]
top-right: Tom buys a car for $12700
top-right: depreciates by 17.5% per a
top-right: Work out how much it
top-right: will be worth after:
top-right: 3 years $ [ ]
top-right: 5 years $ [ ]
top-right: 7 years $ [ ]
top-right: 10 years $ [ ]
bottom-center: Give your answers to the nearest $.
1. **Problem Statement:**
Nishi invests $2700 at an interest rate of 6% per year. We need to find how much she will have after 2, 4, 6, and 10 years.
2. **Formula for Compound Interest:**
$$ A = P(1 + r)^t $$
where:
- $A$ is the amount after $t$ years,
- $P$ is the principal amount,
- $r$ is the annual interest rate (as a decimal),
- $t$ is the number of years.
3. **Calculate Nishi's investment value:**
- Principal $P = 2700$
- Rate $r = 0.06$
Calculate for each $t$:
- For $t=2$:
$$ A = 2700(1 + 0.06)^2 = 2700(1.06)^2 = 2700 \times 1.1236 = 3033.72 $$
Rounded to nearest dollar: $3034$
- For $t=4$:
$$ A = 2700(1.06)^4 = 2700 \times 1.2625 = 3408.75 $$
Rounded: $3409$
- For $t=6$:
$$ A = 2700(1.06)^6 = 2700 \times 1.4185 = 3829.95 $$
Rounded: $3830$
- For $t=10$:
$$ A = 2700(1.06)^{10} = 2700 \times 1.7908 = 4835.16 $$
Rounded: $4835$
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Since the user message contains two distinct problems, but per instructions we solve only the first one completely and count both.
**Final answers for Nishi's investment:**
- After 2 years: $3034$
- After 4 years: $3409$
- After 6 years: $3830$
- After 10 years: $4835$