Question: User: 1.A lot owner bought a piece of land for ₱500,000. The value of the land appreciates by 8% every year. What will be the value of the land after 5 years? Php 680, 244 Php 200, 000 Php 2, 000, 000 Other: 2.Acosta invested ₱30,000 to PNB that grows 3% compounded interest every year. How much will his money be after 2 years? Php 1800 Php 31, 827 Php 18, 000 Other: 3. You borrowed Php 25,000 from a local credit cooperative to expand your sari-sari store. The cooperative charges a 5% simple interest rate per year. How much is the total payment after 3 years? Php 3,750 Php 28,750 Php 375,000 Other: What is the importance of learning about sequence and series? (Write 2-3 sentences) Your answer Graph/shapes: none visible; math is a simple-interest word problem located at top-left to center.can u help me to solve this like one by one?

1. **Problem 1: Land value appreciation** A lot owner bought a piece of land for $500,000$. The value appreciates by $8\%$ every year. We want to find the value after $5$ years. 2. **Formula used:** Compound interest formula for appreciation: $$ A = P \left(1 + \frac{r}{100}\right)^n $$ where $A$ is the amount after $n$ years, $P$ is the principal (initial value), $r$ is the rate of appreciation, and $n$ is the number of years. 3. **Substitute values:** $$ A = 500,000 \left(1 + \frac{8}{100}\right)^5 = 500,000 \times (1.08)^5 $$ 4. **Calculate $(1.08)^5$:** $$ (1.08)^5 = 1.469328 $$ 5. **Calculate final value:** $$ A = 500,000 \times 1.469328 = 734,664 $$ So, the value of the land after 5 years is approximately $734,664$. --- 6. **Problem 2: Compound interest investment** Acosta invested $30,000$ at $3\%$ compounded interest per year. Find the amount after $2$ years. 7. **Formula:** Same compound interest formula: $$ A = P \left(1 + \frac{r}{100}\right)^n $$ 8. **Substitute values:** $$ A = 30,000 \times (1 + \frac{3}{100})^2 = 30,000 \times (1.03)^2 $$ 9. **Calculate $(1.03)^2$:** $$ (1.03)^2 = 1.0609 $$ 10. **Calculate final amount:** $$ A = 30,000 \times 1.0609 = 31,827 $$ So, the amount after 2 years is $31,827$. --- 11. **Problem 3: Simple interest loan** You borrowed $25,000$ at $5\%$ simple interest per year. Find the total payment after $3$ years. 12. **Formula for simple interest:** $$ I = P \times \frac{r}{100} \times t $$ where $I$ is interest, $P$ is principal, $r$ is rate, and $t$ is time in years. 13. **Calculate interest:** $$ I = 25,000 \times \frac{5}{100} \times 3 = 25,000 \times 0.05 \times 3 = 3,750 $$ 14. **Total payment:** $$ \text{Total} = P + I = 25,000 + 3,750 = 28,750 $$ So, the total payment after 3 years is $28,750$. --- **Final answers:** 1. Land value after 5 years: $734,664$ (not listed in options, so "Other") 2. Investment after 2 years: $31,827$ 3. Total payment after 3 years: $28,750$