Question: Find the present value of an ordinary annuity with deposits of $12,546 quarterly for 7 years at 11.2% compounded quarterly.
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Part 1
What is the present value?
1. **State the problem:** We need to find the present value of an ordinary annuity with quarterly deposits of $12,546 for 7 years at an interest rate of 11.2% compounded quarterly.
2. **Formula for present value of an ordinary annuity:**
$$PV = P \times \frac{1 - (1 + r)^{-n}}{r}$$
where:
- $P$ is the payment per period
- $r$ is the interest rate per period
- $n$ is the total number of payments
3. **Identify values:**
- $P = 12546$
- Annual interest rate = 11.2%, so quarterly rate $r = \frac{11.2}{4} \% = 2.8\% = 0.028$
- Number of years = 7, so total payments $n = 7 \times 4 = 28$
4. **Calculate present value:**
$$PV = 12546 \times \frac{1 - (1 + 0.028)^{-28}}{0.028}$$
5. **Calculate $(1 + r)^{-n}$:**
$$ (1 + 0.028)^{-28} = \frac{1}{(1.028)^{28}} $$
Calculate $(1.028)^{28}$:
$$ (1.028)^{28} \approx 2.123 $$
So,
$$ (1 + 0.028)^{-28} = \frac{1}{2.123} \approx 0.471 $$
6. **Substitute back:**
$$PV = 12546 \times \frac{1 - 0.471}{0.028} = 12546 \times \frac{0.529}{0.028}$$
7. **Simplify fraction:**
$$ \frac{0.529}{0.028} \approx 18.89 $$
8. **Final multiplication:**
$$PV = 12546 \times 18.89 \approx 237,000.54$$
**Answer:** The present value of the ordinary annuity is approximately $237,000.54$.