Question: Find the measure of angle B given an exterior angle of 150° at D and an interior angle of 40° at C in a triangle-like diagram.
1. **State the problem:** We need to find the measure of angle $B$ in a triangle where the exterior angle at vertex $D$ is $150^\circ$ and the interior angle at vertex $C$ is $40^\circ$.
2. **Recall the exterior angle theorem:** The exterior angle of a triangle is equal to the sum of the two opposite interior angles. Mathematically, if $\angle D$ is the exterior angle, then:
$$\angle D = \angle B + \angle C$$
3. **Substitute the known values:**
$$150^\circ = \angle B + 40^\circ$$
4. **Solve for $\angle B$:**
$$\angle B = 150^\circ - 40^\circ$$
5. **Calculate:**
$$\angle B = 110^\circ$$
6. **Conclusion:** The measure of angle $B$ is $110^\circ$.