Question: Q1
p = doc.add_paragraph() p.add_run("1. (a) ").bold = True p.add_run("In the diagram, MNPS is a quadrilateral. A line is drawn through N to cut SP at Q. Angle MNQ = 132\u00b0, angle SMN is twice angle MSQ and angle NPQ is twice angle QNP. If NP bisects the acute angle at N, find:") doc.add_picture(diagram1_path, width=Inches(5.4)) doc.paragraphs[-1].alignment = WD_ALIGN_PARAGRAPH.CENTER for text in ["i. Angle SQN.", "ii. Angle MSQ."]: p = doc.add_paragraph(text) p.paragraph_format.left_indent = Inches(0.35)
1. **Problem Statement:**
In quadrilateral MNPS, a line through point N cuts SP at Q. Given:
- $\angle MNQ = 132^\circ$
- $\angle SMN = 2 \times \angle MSQ$
- $\angle NPQ = 2 \times \angle QNP$
- $NP$ bisects the acute angle at $N$
Find:
(i) $\angle SQN$
(ii) $\angle MSQ$
2. **Understanding the problem and notation:**
- Since $NP$ bisects the acute angle at $N$, let the acute angle at $N$ be $2x$, so each bisected angle is $x$.
- Let $\angle QNP = y$, then $\angle NPQ = 2y$.
- Let $\angle MSQ = z$, then $\angle SMN = 2z$.
3. **Using the given angles and relationships:**
- From the quadrilateral and line properties, we analyze angles around point $N$ and on line $SP$.
- Since $\angle MNQ = 132^\circ$, and $NP$ bisects the acute angle at $N$, the angles around $N$ must satisfy:
$$\angle MNQ + \angle QNP + \angle NPQ = 180^\circ$$
Substitute $\angle MNQ = 132^\circ$, $\angle QNP = y$, $\angle NPQ = 2y$:
$$132 + y + 2y = 180$$
$$132 + 3y = 180$$
$$3y = 48$$
$$y = 16^\circ$$
4. **Find $\angle SQN$:**
- $\angle SQN$ is supplementary to $\angle NPQ$ on line $SP$:
$$\angle SQN + \angle NPQ = 180^\circ$$
Substitute $\angle NPQ = 2y = 32^\circ$:
$$\angle SQN = 180 - 32 = 148^\circ$$
5. **Find $\angle MSQ$:**
- Given $\angle SMN = 2 \times \angle MSQ$, let $\angle MSQ = z$, so $\angle SMN = 2z$.
- Since $\angle MNQ = 132^\circ$ and $\angle SMN = 2z$, angles around point $M$ in triangle $MSN$ satisfy:
$$\angle SMN + \angle MSQ + \angle MNQ = 180^\circ$$
Substitute:
$$2z + z + 132 = 180$$
$$3z = 48$$
$$z = 16^\circ$$
**Final answers:**
- (i) $\angle SQN = 148^\circ$
- (ii) $\angle MSQ = 16^\circ$