Question: User: 26 / 30
3x°
(2x + 16)°
Find the value of x
8
16
32.8
39.2
Graph/shape: A small line-intersection angle diagram appears in the top-left; one angle is labeled 3x° and the adjacent angle is labeled (2x + 16)°, indicating intersecting lines with supplementary angles. position_hint ∈ {top-left}
1. **State the problem:** We are given two adjacent angles formed by intersecting lines: one angle is $3x^\circ$ and the other is $(2x + 16)^\circ$. We need to find the value of $x$.
2. **Recall the rule:** Adjacent angles formed by intersecting lines are supplementary, meaning their measures add up to $180^\circ$.
3. **Set up the equation:**
$$3x + (2x + 16) = 180$$
4. **Simplify the equation:**
$$3x + 2x + 16 = 180$$
$$5x + 16 = 180$$
5. **Isolate $x$:**
$$5x = 180 - 16$$
$$5x = 164$$
6. **Divide both sides by 5:**
$$x = \frac{164}{5}$$
7. **Simplify the fraction:**
$$x = 32.8$$
**Final answer:** $x = 32.8$