1. **Problem statement:** We have a circle with center $P$ and diameters $FH$ and $EG$. We need to find the measure of arc $DGE$.
2. **Given information:**
- $FH$ and $EG$ are diameters, so they pass through the center $P$ and their endpoints lie on the circle.
- The central angle between $PH$ and $PG$ is $38^\circ$.
- There is a right angle ($90^\circ$) between $PD$ and $PH$.
3. **Key concepts:**
- The measure of an arc is equal to the measure of its central angle.
- Since $FH$ and $EG$ are diameters, points $F$, $H$, $E$, and $G$ lie on the circle and $P$ is the center.
- The central angle between two points on the circle is the angle formed at the center by the radii to those points.
4. **Step-by-step solution:**
- Since $FH$ is a diameter, points $F$ and $H$ are opposite ends of the circle.
- Similarly, $EG$ is a diameter, so points $E$ and $G$ are opposite ends.
- The central angle between $PH$ and $PG$ is $38^\circ$, so the angle $\angle HPG = 38^\circ$.
- The right angle between $PD$ and $PH$ means $\angle DPH = 90^\circ$.
5. **Find the central angle $\angle DPG$:**
- $\angle DPG = \angle DPH + \angle HPG = 90^\circ + 38^\circ = 128^\circ$.
6. **Arc $DGE$ corresponds to central angle $\angle DPG$ because $E$ and $G$ are endpoints of diameter $EG$ and $D$ lies on the circle between $G$ and $E$. So the measure of arc $DGE$ is $128^\circ$.
**Final answer:**
$$\boxed{128^\circ}$$
The correct choice is C.
Arc Dge 0C30Ae
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