Subjects geometry

Area Equality Cffacf

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Question: The rectangle and triangle below have the same area. Calculate $d$. Calculator not allowed 8 cm 5 cm 5 cm $d$ Not to scale Rectangle (left, center-left): a purple rectangle with height 8 cm and width 5 cm. Triangle (right, center-right): a yellow triangle with base $d$ and perpendicular height 5 cm.
1. **State the problem:** We have a rectangle and a triangle with the same area. The rectangle has height $8$ cm and width $5$ cm. The triangle has base $d$ cm and height $5$ cm. We need to find $d$. 2. **Formula for area:** - Area of rectangle = height $\times$ width - Area of triangle = $\frac{1}{2} \times$ base $\times$ height 3. **Calculate the area of the rectangle:** $$\text{Area}_{\text{rectangle}} = 8 \times 5 = 40 \text{ cm}^2$$ 4. **Set the areas equal:** Since the areas are the same, $$40 = \frac{1}{2} \times d \times 5$$ 5. **Solve for $d$:** Multiply both sides by 2 to eliminate the fraction: $$2 \times 40 = \cancel{2} \times \frac{1}{\cancel{2}} \times d \times 5 \implies 80 = d \times 5$$ Divide both sides by 5: $$\frac{80}{\cancel{5}} = d \times \frac{\cancel{5}}{5} \implies 16 = d$$ 6. **Final answer:** $$d = 16 \text{ cm}$$ This means the base of the triangle is $16$ cm to have the same area as the rectangle.
8 cm5 cm16 cm5 cm