1. **Problem Statement:** In circle $\odot O$, chord $AB$ and segment $OC$ intersect at point $M$. Given that $OM = MC$ and $AM = 1.5$, $BM = 4$, find the length of $OC$.
2. **Relevant Theorem:** When two chords intersect inside a circle, the products of the segments of each chord are equal. This is called the Intersecting Chords Theorem.
3. **Formula:** If chords $AB$ and $CD$ intersect at $M$, then:
$$AM \times MB = CM \times MD$$
4. **Apply to our problem:** Here, $AB$ is a chord with segments $AM = 1.5$ and $BM = 4$. The segment $OC$ is divided into two equal parts by $M$, so $OM = MC = x$ (unknown).
5. Using the theorem:
$$AM \times BM = OM \times MC$$
$$1.5 \times 4 = x \times x$$
$$6 = x^2$$
6. Solve for $x$:
$$x = \sqrt{6}$$
7. Since $OC = OM + MC = x + x = 2x$, then:
$$OC = 2 \times \sqrt{6} = 2\sqrt{6}$$
**Final answer:**
$$OC = 2\sqrt{6}$$
Chord Intersection A922Ad
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