Question: A circle in the $(x,y)$-coordinate plane is given by the equation $$(x-5)^2 + y^2 = 49$$. What is the area of the circle, in square units?
1. **State the problem:** We are given the equation of a circle $$(x-5)^2 + y^2 = 49$$ and need to find its area in square units.
2. **Recall the formula for the area of a circle:** The area $A$ of a circle with radius $r$ is given by $$A = \pi r^2$$.
3. **Identify the radius from the equation:** The given equation is in the standard form of a circle $$(x-h)^2 + (y-k)^2 = r^2$$ where $(h,k)$ is the center and $r$ is the radius.
4. From the equation $$(x-5)^2 + y^2 = 49$$, we see that $$r^2 = 49$$, so $$r = \sqrt{49} = 7$$.
5. **Calculate the area:** Substitute $$r=7$$ into the area formula:
$$A = \pi (7)^2 = 49\pi$$.
6. **Answer:** The area of the circle is $$49\pi$$ square units.
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**Similar problem:**
Find the area of the circle given by the equation $$(x+3)^2 + (y-4)^2 = 36$$.